What is 0X0 0X0 Error Message All About?

The title must have been enough for you to get insights into what we are going to talk about. This is quite a popular error faced by a large number of people. We are going to discuss it in detail here. We decided to write an article on the 0X0 0X0 issue because a large number of people were asking about it on the internet. Since the queries associated with it are flooding online, addressing this issue became the need of the hour. So, let us get started without much delay. 

What is this 0X0 0X0 Error All About?

There is a large number of things you need to know about this error before you jump right to the solution section. This error occurs in several situations. In order to make things clear for you, here is a look at the most common program that gives this error after running. 

package main

import (

    // “fmt”

“html/template”

“log”

“math/rand”

“net/http”

“time”

    // “golang.org/x/mobile/app”

)

func main() {

http.HandleFunc(“/”, randNum)

log.Fatal(http.ListenAndServe(“:8080”, nil))

}

func randNum(w http.ResponseWriter, r *http.Request) {

    // Create random number

aRand := rand.Intn(100)

    type RNumber struct {

A int

    }

    Rnum := RNumber{aRand}

//Show Template

Tmp1, err := template.New(“randNum1”).Parse(“HTML NUMBER ======> {{.A}} “)

    if err != nil {

print(err)

    }

    err = Tmp1.Execute(w, Rnum)

print(err)//<==========Error (0x0 0x0)

time.Sleep(3000 * time.Millisecond)

//Loop

    randNum(w, r)

}

Taking a look at this code you may find some reasons behind the occurrence of this issue. Some people call it a loop but it is not. When you are generating an output, you must return it in order to flush the connection. This way you will be able to terminate the program. In this program, you simply initiate a recursion that never terminates and the overflow is the result. 

Final words

We hope this article helped you get familiar with the viable solutions to this 0X0 0X0 issue. Follow us for more articles like this.